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What is the mass of a cylinder of lead with a radius of 1 centimeter and a height of 3 centimeters, given that the density of lead is ?

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Answer:

106.78 g

Explanation:

For lead, d = 11.33 g/cm³.

V = πr²h

m = Vd

m = π × (1 cm)² × 3 cm × 11.33 g/cm³

m = 106.78 g

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