43.4k views
4 votes
28n⁴ + 16n³ - 80n²


Factor completely show work pls

User Jndok
by
8.6k points

2 Answers

2 votes
28n^4 + 16n^3 - 80n^2

Start with 28n^4 + 16n^3 which is 44n^7 as you add the powers and integers together
Then do 44n^7 - 80n^2 which is -36n^5 as you subtract the powers and integers.

So the answer is -36n^5
User Bao
by
8.5k points
2 votes

Answer:

4n²(7n-10)(n+2)

Explanation:

  • 28n⁴ + 16n³ - 80n².

The first step is to factor out a 4n² or take common from each term:

  • 28n⁴ + 16n³ - 80n²
  • 4n²(7n² + 4n - 20)

The next step is to factor 7n² + 4n - 20. We can do this by grouping:

  • 7n² + 4n - 20
  • (7n² + 14n - 10n - 20)
  • 7n(n+2)-10(n+2)
  • (n+2)(7n-10)

Therefore, the complete factorization is:

  • 4n²(7n-10)(n+2)
User Charles Roth
by
9.6k points

Related questions

1 answer
2 votes
191k views
1 answer
2 votes
89.7k views
asked Apr 11, 2020 167k views
David Mason asked Apr 11, 2020
by David Mason
8.3k points
2 answers
0 votes
167k views