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an airplane releases a parcel while moving at a horizontal speed of 80m/s at an attitude 260m.Calculate the time between the parcel leaving the airplane and it striking the ground.Calculate the horizontal distace traveled by the parcel in this time

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The horizontal distance traveled by the parcel in this time is approximately 581.6 meters.

Given - Initial horizontal speed of the airplane (u) = 80 m/s

Altitude (h) = 260 m

Acceleration due to gravity (g) = 9.8 m/s^2

To find - the horizontal distance traveled by the parcel in this time

Solution -

First, let's calculate the time (t) it takes for the parcel to reach the ground:

Using the equation for vertical motion:

h = ut + (1/2)gt^2

Rearranging the equation and substituting the known values:

260 = 0t + (1/2)(9.8)t^2

Rearranging again:

4.9t^2 = 260

Dividing both sides by 4.9:

t^2 = 52.94

Taking the square root of both sides:

t ≈ 7.27 s

Therefore, it takes approximately 7.27 seconds for the parcel to strike the ground.

Next, let's calculate the horizontal distance (d) traveled by the parcel in this time:

Using the equation for horizontal motion:

d = ut

Substituting the known values:

d = 80 m/s * 7.27 s

d ≈ 581.6 m

Therefore, the horizontal distance traveled by the parcel is approximately 581.6 meters.

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