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Factorise 9x^2 +4y^2+Z^2-12xy+4yz-6xz
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To factorize the expression 9x^2 + 4y^2 + z^2 - 12xy + 4yz - 6xz quickly, we can use grouping and rearrange the terms:

(9x^2 - 12xy - 6xz) + (4y^2 + 4yz) + z^2

Now, let's factor each grouped term separately:

Factor out 3x from the first group: 3x(3x - 4y - 2z)

Factor out 4y from the second group: 4y(y + z)

The third group, z^2, cannot be factored any further.

Putting it all together, we have the factored form:

3x(3x - 4y - 2z) + 4y(y + z) + z^2

Please note that this is the simplified form of the expression, but it may not necessarily be further factorizable.

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