Answer:
The number of vertices in the polyhedron can be found using Euler's formula:
V + F = E + 2
where V is the number of vertices, F is the number of faces, and E is the number of edges.
We are given that the polyhedron has 30 squares, 20 triangles, and 12 pentagons. Since each square has 4 sides, each triangle has 3 sides, and each pentagon has 5 sides, the total number of sides in the polyhedron is:
30 x 4 + 20 x 3 + 12 x 5 = 120 + 60 + 60 = 240
We are also given that the polyhedron has 120 edges, so:
E = 120
Finally, we can substitute these values into Euler's formula and solve for V:
V + F = E + 2
V + 30 + 20 + 12 = 120 + 2
V + 62 = 122
V = 60
Therefore, the polyhedron has 60 vertices. Answer: 60.