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In simplest radical form, what are the solutions to the quadratic equation 0 = −3x² - 4x + 5? Quadratic formula x = - b ± √b² 2

a= - 24/19 3 X O
x = -- = -2±2/19 3
O x = 2+√19 3 2+2√19 3 4 ​

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Answer: In simplest radical form, what are the solutions to the quadratic equation 0 = −3x² - 4x + 5? Quadratic formula x = - b ± √b² 2

a= - 24/19 3 X O

x = -- = -2±2/19 3

O x = 2+√19 3 2+2√19 3 4 ​

ChatGPT

To find the solutions to the quadratic equation 0 = -3x² - 4x + 5, we can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a)

In this equation, a = -3, b = -4, and c = 5. Substituting these values into the quadratic formula, we get:

x = (-(-4) ± √((-4)² - 4(-3)(5))) / (2(-3))

Simplifying further:

x = (4 ± √(16 + 60)) / (-6)

x = (4 ± √76) / (-6)

x = (4 ± √(4 * 19)) / (-6)

x = (4 ± 2√19) / (-6)

Simplifying the expression:

x = (2(2 ± √19)) / (-6)

x = (2 ± √19) / (-3)

Therefore, the solutions to the quadratic equation are:

x = (2 + √19) / (-3)

x = (2 - √19) / (-3)

These solutions cannot be simplified any further in terms of radicals.

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