Answer: In simplest radical form, what are the solutions to the quadratic equation 0 = −3x² - 4x + 5? Quadratic formula x = - b ± √b² 2
a= - 24/19 3 X O
x = -- = -2±2/19 3
O x = 2+√19 3 2+2√19 3 4
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To find the solutions to the quadratic equation 0 = -3x² - 4x + 5, we can use the quadratic formula:
x = (-b ± √(b² - 4ac)) / (2a)
In this equation, a = -3, b = -4, and c = 5. Substituting these values into the quadratic formula, we get:
x = (-(-4) ± √((-4)² - 4(-3)(5))) / (2(-3))
Simplifying further:
x = (4 ± √(16 + 60)) / (-6)
x = (4 ± √76) / (-6)
x = (4 ± √(4 * 19)) / (-6)
x = (4 ± 2√19) / (-6)
Simplifying the expression:
x = (2(2 ± √19)) / (-6)
x = (2 ± √19) / (-3)
Therefore, the solutions to the quadratic equation are:
x = (2 + √19) / (-3)
x = (2 - √19) / (-3)
These solutions cannot be simplified any further in terms of radicals.