Answer:
a) Let's say the number of owls is "x" and the number of foxes is "y".
Each owl has 2 eyes and 2 legs, so "x" owls would have 2x eyes and 2x legs.
Each fox has 2 eyes and 4 legs, so "y" foxes would have 2y eyes and 4y legs.
According to the problem, there are 22 eyes and 32 legs in total:
2x + 2y = 22 (equation 1)
2x + 4y = 32 (equation 2)
We can use these two equations to solve for "x" and "y".
Subtracting equation 1 from equation 2:
2x + 4y - (2x + 2y) = 32 - 22
2y = 10
y = 5
Substituting "y" = 5 into equation 1:
2x + 2(5) = 22
2x = 12
x = 6
Therefore, there are 6 owls and 5 foxes.
b) Let's use the same approach to solve for "x" and "y":
2x + 2y = 24 (equation 1')
2x + 4y = 38 (equation 2')
Subtracting equation 1' from equation 2':
2x + 4y - (2x + 2y) = 38 - 24
2y = 14
y = 7
Substituting "y" = 7 into equation 1':
2x + 2(7) = 24
2x = 10
x = 5
Therefore, there are 5 owls and 7 foxes.