
The first subset contains 1 number, the second subset contains 2 numbers, the third subset contains 3 numbers, and so on. So the nth subset contains n numbers.
To find the first number in the nth subset, we need to find the sum of the first n-1 numbers. The sum of the first n-1 numbers is given by the formula:
1 + 2 + 3 + ... + (n-1) = (n-1)(n-2)/2
Therefore, the first number in the nth subset is:
(n-1)(n-2)/2+1
Simplifying this expression gives:
(n^2 - 3n + 2)/2
So the formula for the first member of the nth subset is (n^2 - 3n + 2)/2.