Question

A sample of NaOH weighing 0.38g is dissolved in water the

solution is made to 50ml in volumetric flask. What is the molarity of
the resulting solution

Answer 1

The required molarity of the resulting solution is :

• 0.4 M

Step-by-step explanation:

Molarity is defined as the number of moles of solute dissolved per litre of solution.

Formula :

`\pmb{ m = \frac {Number \: of \: moles \: of \: solute}{Volume \: of \: {sol}^(n) (ml) } * 1000}`

Here we are given .

• Mass of NaOH = 0.38 g
• Molar mass of NaOH = 40 g

No. of moles = Given mass/Molar Mass

• No. of moles = 0.38/40
• No. of moles = 0.02 g
• Volume of solution= 50 ml

So Simply by plugging in the values of moles of solute and volume of solution in the above formula we will get the required Molarity of the resulting solution..

`\rightarrow \rm M = (0.02)/(50) * 1000 \\ \\ \rightarrow \rm M = 0.0004 * 1000 \\ \\ \rightarrow \rm { \underline{M = 0.4 \: M}}`

So The required Molarity of the resulting solution is 0.4 M