Let's assume the original mass of the saline water (salt water) is x grams. According to the given information, the mass ratio of salt to water is initially 1:10.
This means the mass of salt in the saline water is (1/11) * x grams, and the mass of water is (10/11) * x grams.
After adding 22 grams of salt, the mass ratio of salt to water becomes 2:9.
This means the mass of salt is now (2/11) * (x + 22) grams, and the mass of water is (9/11) * (x + 22) grams.
Since the mass of salt remains the same in both scenarios, we can set up an equation:
(1/11) * x = (2/11) * (x + 22)
Simplifying the equation:
x = 2 * (x + 22)
x = 2x + 44
x - 2x = 44
-x = 44
x = -44 (disregard this negative value)
Since the value of x is negative, it is not a valid solution in this context.
It seems there may be an error or inconsistency in the given information or calculations. Please double-check the values and ratios provided to ensure accuracy.