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Acetone has a density of 0.7857 g/cm3. What would be the volume in mL of acetone if the mass was 0.3201 lbs? Remember 1 lb = 0.453 kg

A. 184.8 mL
B. 0.8982 mL
C. 251.5 mL
D. 0.1848 mL
E. 114.3 mL

1 Answer

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To solve this problem, we can use the given density of acetone and convert the mass from pounds to grams.

First, let's convert the mass from pounds to kilograms:


\displaystyle \text{Mass (kg)} = 0.3201 * 0.453 = 0.14517 \,\text{kg}

Now, we can use the density formula to find the volume in cubic centimeters (cm³):


\displaystyle \text{Density} = \frac{{\text{Mass}}}{{\text{Volume}}}

Rearranging the formula to solve for volume, we have:


\displaystyle \text{Volume (cm}^(3)\text{)} = \frac{{\text{Mass}}}{{\text{Density}}}

Substituting the given values, we get:


\displaystyle \text{Volume (cm}^(3)\text{)} = \frac{{0.14517\,\text{kg}}}{{0.7857\,\text{g/cm}^(3)}}

Now, let's convert the volume from cubic centimeters to milliliters:


\displaystyle \text{Volume (mL)} = \text{Volume (cm}^(3)\text{)}

Substituting the value we obtained earlier, we have:


\displaystyle \text{Volume (mL)} = \frac{{0.14517\,\text{kg}}}{{0.7857\,\text{g/cm}^(3)}}

Calculating the value, we find:


\displaystyle \text{Volume (mL)} = 184.77\,\text{mL}

Therefore, the volume of acetone would be approximately 184.8 mL.

The correct option is A. 184.8 mL.


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