Question

There were 386 tickets purchased for a major league baseball game. The tickets cost ​$ 6.50 and the tickets cost ​$10.00. The total amount of money spent was ​$3576.50. How many of each kind of ticket were​ purchased?

Answer 1

• 81 tickets at $6.50
• 305 tickets at $10.00

Explanation:

You want the number of tickets sold at prices of $6.50 and $10 if 386 tickets were sold for $3576.50.

Setup

The number of $6.50 ticket is (386 -x) if x tickets were sold at $10. The total revenue will be ...

10x +6.50(386 -x) = 3576.50

Solution

3.50x +2509 = 3576.50 . . . . . simplify

3.50x = 1067.50 . . . . . . . . . . . subtract 2509

x = 305 . . . . . . . . . . . . . . . . . . divide by 3.50

386 -x = 81 . . . . . . . . . find the number of cheap seats

305 tickets were sold for $10; 81 tickets were sold for $6.50.

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