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Solve the system.

x + y = 8
2x2 – y = –5

Add the equations, then choose the result.

3x2 = –13

3x2 = 3

2x2 + x = 3

2x2 = –13

User Tnkh
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1 Answer

4 votes

Answer:

To solve the system of equations:

x + y = 8

2x^2 - y = -5

We can use the method of substitution or elimination. Let's use the elimination method to solve this system.

First, let's multiply the first equation by 2 to match the coefficients of x^2:

2(x + y) = 2(8)

2x + 2y = 16

Now, we can subtract the second equation from this new equation:

2x + 2y - (2x^2 - y) = 16 - (-5)

2x + 2y - 2x^2 + y = 16 + 5

2y + y - 2x^2 + 2x = 21

Simplifying the equation:

3y - 2x^2 + 2x = 21

Now, let's rearrange this equation:

2x^2 - 2x - 3y = -21

This is a quadratic equation in terms of x. To further solve for x or y, we need another equation or more information.

If you have any additional equations or information related to the system, please provide them, and I will be happy to assist you further.

Explanation:

User Bhargav Chudasama
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