Calculating the z-score:
z = (3.0 - 2.5) / (0.866 / sqrt(25))
z = 0.5 / (0.866 / 5)
z ≈ 2.886
Now, we can use a standard normal distribution table or calculator to find the probability corresponding to a z-score of 2.886. The probability that the sample mean GPA is greater than 3.0 can be approximated by the area under the standard normal curve from 2.886 to infinity. This probability corresponds to approximately 0.0019 (or 0.19%).
Therefore, the approximate probability that, in a random sample of 25 students from this school, the sample mean GPA is greater than 3.0 is approximately 0.19%.