Question

2) a second crazed physics student, sandro, throws another pumpkin from the same place as leonardo, but throws his pumpkin straight up at 19.4 m/s. (a) what is the velocity of the pumpkin as it passes by sandro on its way down? (b) determine the velocity of the pumpkin just before it strikes the ground. (c) how long does it take to hit the ground?

Answer 1

The velocity of the pumpkin as it passes by Sandro on its way down is -19.4 m/s. The velocity of the pumpkin just before it strikes the ground is also -19.4 m/s. The time it takes to hit the ground depends on the height from which it is thrown.

Step-by-step explanation:

In this problem, Sandro throws the pumpkin straight up with an initial velocity of 19.4 m/s. So, when the pumpkin passes by Sandro on its way down, its velocity would be equal to the initial velocity with a negative sign, which is -19.4 m/s.

When the pumpkin strikes the ground, its final velocity would be the same magnitude as the initial velocity with a negative sign, so it would be -19.4 m/s.

To determine the time it takes for the pumpkin to hit the ground, we can use the equation h = (1/2)gt2, where h is the height, g is the acceleration due to gravity (approximately 9.8 m/s2), and t is the time. The height is not given, so we can't calculate the exact time it takes for the pumpkin to hit the ground. However, if we assume the ground is at 0 height, we can solve for t.

Answer 2

When the pumpkin passes Sandro on its way down, its velocity will be 0 m/s. Just before striking the ground, the velocity of the pumpkin will be 19.4 m/s. It will take approximately 2 seconds for the pumpkin to hit the ground.

Step-by-step explanation:

To find the velocity of the pumpkin as it passes by Sandro on its way down, we first need to calculate the time it takes for the pumpkin to reach its highest point. Using the equation v = u + at, where v is the final velocity (0 m/s), u is the initial velocity (19.4 m/s), a is the acceleration due to gravity (-9.8 m/s²) and t is the time, we can solve for t to find that it takes approximately 2 seconds.

With this information, we can then find the velocity of the pumpkin as it passes by Sandro on its way down. Since the velocity at the highest point is 0 m/s, the velocity as it passes by Sandro on its way down will also be 0 m/s.

To determine the velocity of the pumpkin just before it strikes the ground, we can use the equation v = u + at, where v is the final velocity, u is the initial velocity (0 m/s), a is the acceleration due to gravity (-9.8 m/s²) and t is the time. Solving for v, we find that the velocity of the pumpkin just before it strikes the ground is approximately 19.4 m/s.

Finally, to calculate the time it takes for the pumpkin to hit the ground, we can use the equation s = ut + 0.5at², where s is the distance traveled (the height from which it was thrown), u is the initial velocity (19.4 m/s), a is the acceleration due to gravity (-9.8 m/s²), and t is the time. Solving for t, we find that it takes approximately 2 seconds for the pumpkin to hit the ground.