Question

(6-2x) +(15-3x) where x=0.2

Answer 1

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Expression:
`\displaystyle\sf (6-2x) +(15-3x)`

Substituting
`\displaystyle\sf x=0.2`:

`\displaystyle\sf (6-2(0.2)) +(15-3(0.2))`

Simplifying the expression inside the parentheses:

`\displaystyle\sf (6-0.4) +(15-0.6)`

`\displaystyle\sf 5.6 +14.4`

Calculating the sum:

`\displaystyle\sf 20`

Therefore,
`\displaystyle\sf (6-2x) +(15-3x)` evaluated at
`\displaystyle\sf x=0.2` is equal to
`\displaystyle\sf 20`.

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