(6-2x) +(15-3x) where x=0.2

Question

asked Jun 8, 2024 234k views

1 Answer

Seer · Answer 1 · 2024-06-14T23:52:34+0000

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Expression:
$\displaystyle\sf (6-2x) +(15-3x)$

Substituting
$\displaystyle\sf x=0.2$ :

$\displaystyle\sf (6-2(0.2)) +(15-3(0.2))$

Simplifying the expression inside the parentheses:

$\displaystyle\sf (6-0.4) +(15-0.6)$

$\displaystyle\sf 5.6 +14.4$

Calculating the sum:

$\displaystyle\sf 20$

Therefore,
$\displaystyle\sf (6-2x) +(15-3x)$ evaluated at
$\displaystyle\sf x=0.2$ is equal to
$\displaystyle\sf 20$ .

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