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(6-2x) +(15-3x) where x=0.2

User Taelsin
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Expression:
\displaystyle\sf (6-2x) +(15-3x)

Substituting
\displaystyle\sf x=0.2:


\displaystyle\sf (6-2(0.2)) +(15-3(0.2))

Simplifying the expression inside the parentheses:


\displaystyle\sf (6-0.4) +(15-0.6)


\displaystyle\sf 5.6 +14.4

Calculating the sum:


\displaystyle\sf 20

Therefore,
\displaystyle\sf (6-2x) +(15-3x) evaluated at
\displaystyle\sf x=0.2 is equal to
\displaystyle\sf 20.


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User Seer
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