37.4k views
5 votes
an ecology center wants to set up an experimental garden in the shape of a rectangle. the length of the rectangle is 4 yards longer than the width. what are the dimensions of the garden if the enclosed area is 21 square yards. state units.

1 Answer

1 vote
This is a problem that involves some algebra as well.

Let’s assume that the width of the rectangle is x.
Since the length is 4 yards longer, we can write the length as x + 4.
The area of a rectangle is length * width, and the area is already given to us as 21 square yards.
So length * width = area, meaning x * x + 4 = 21
So x^2 + 4 = 21
= x^2 = 21 - 4
= x^2 = 17
= x = root of 17
= 4.12 yards

We’ve found out that the width is 4.12 yards, so the length must by 4.12 + 4
= 8.12 yards.
So, the dimensions of the garden are 8.12 * 4.12 yards*

*This answer is rounded, so it won’t be exact.
Another, more exact value is root 17 * root 17 + 4
User Pardeep Kumar
by
8.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories