Assume that adults have iq scores that are normally distributed, with a mean of 107 and a standard deviation of 15. find the probability that a randomly selected individual has an iq between 75 and 117.

asked Sep 13, 2024 183k views

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3 votes

Answer:

0.732

Explanation:

$\displaystyle P(75 < X < 117)\\\\=P\biggr((75-107)/(15) < Z < (117-107)/(15)\biggr)\\\\\approx P(-2.13 < Z < 0.67)\\\\\approx0.732$

Consult a z-table to determine this value

Tennile answered Sep 19, 2024

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