If 8. 0 ml of water is added to 2. 0 ml of a 0. 500 m naoh solution, the concentration of naoh is changed to.

asked Jun 25, 2024 180k views

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2 votes

Answer:

0.1mol/dm^3

Step-by-step explanation:

C1=0.5mol/dm^3

V1=2ml

V2=2ml+8ml=10ml

C2= (C1×V1)÷V2

=(0.5×2)÷10

=0.1mol/dm^3

Tanvirgeek answered Jul 1, 2024

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