Question

An electron (charge−1.6× 10−19 c) moves on a path perpendicular to the direction of a uniform electric field of strength 2.0 n/c. how much work is done on the electron as it moves 14.0 cm?

Answer 1

Electric field intensity/strength = Force /Charge
I.e E=F/C
F=E x C
F= 2 x -1.6 x10^-19 C
F= -3.2 x 10^-19 N
Work done = F x D
= -3.2 x 10^-19 N x 14/100
=0.448 x 10^-19

Note:use of x is sign of multiplication