Final answer:
The vector equation for the line of intersection of the planes x+y+z=2 and x+z=0 is r(t) = -ti + 2j - tj.
Step-by-step explanation:
To find a vector equation for the line of intersection of the planes x+y+z=2 and x+z=0, we can solve these two equations simultaneously. From the second equation, we have x = -z. Substituting this into the first equation, we get -z+y+z=2, which simplifies to y=2. Therefore, the line of intersection is given by the parameterized equation r(t) = -ti + 2j - tj, where t is a real number.