Question

consider two capacitors, one with capacitance 15.3 μf and the other of unknown capacitance. the two capacitors are connected in series with a voltage difference of 305 v applied across the capacitors. as a result, the unknown capacitor has a charge of 1.83 mc. find its capacitance.

Answer 1

To find the unknown capacitance, we use the formula Q = CV, where Q is the charge, C is the capacitance, and V is the voltage. By setting the charge on the unknown capacitor equal to the charge on the known capacitor and solving for the unknown capacitance, we can find its value.

Step-by-step explanation:

To find the unknown capacitance, we can use the formula Q = CV, where Q is the charge, C is the capacitance, and V is the voltage. Since the two capacitors are connected in series, the charge on each capacitor must be the same. We know that the charge on the unknown capacitor is 1.83 μC and the voltage across the capacitors is 305 V. Let's assume the unknown capacitance is x μF. Using the formula, we have 1.83 μC = (15.3 μF + x μF) * 305 V. We can solve this equation to find the value of x.

Answer 2

The capacitance of the unknown capacitor is approximately 6 μF.

Step-by-step explanation:

To find the capacitance of the unknown capacitor, we can use the formula Q = CV, where Q is the charge, C is the capacitance, and V is the voltage difference. In this case, the charge on the unknown capacitor is given as 1.83 mc, and the voltage difference is 305 V. Plugging these values into the formula, we get:

1.83 mc = C * 305 V

Rearranging the equation, we can solve for the unknown capacitance:

C = (1.83 mc) / (305 V)

Converting the charge to coulombs and simplifying, we find that the capacitance of the unknown capacitor is approximately 6 microfarads (μF).