The python code for the list of string is shown below
def roman_to_decimal(roman):
roman_numerals = {'I': 1, 'V': 5, 'X': 10, 'L': 50}
decimal = 0
prev_value = 0
for numeral in reversed(roman):
value = roman_numerals[numeral]
if value < prev_value:
decimal -= value
else:
decimal += value
prev_value = value
return decimal
def custom_sort(name_with_roman):
name, roman = name_with_roman.split()
return (name, roman_to_decimal(roman))
def sort_names(names):
sorted_names = sorted(names, key=custom_sort)
return sorted_names
# Example usage
names = ['Steven XL', 'Steven XVI', 'David IX', 'Mary XV', 'Mary XIII', 'Mary XX']
sorted_names = sort_names(names)
print(sorted_names)
names = ['Steven XL', 'Steven XVI', 'David IX', 'Mary XV', 'Mary XIII', 'Mary XX']
print(sort_by_name_and_roman_numeral(names))
To be able to do the code, one can create a custom sorting function that first separates the name and Roman numeral, converts the Roman numeral to its decimal equivalent, and then sorts the list accordingly.
The above script tells a roman_to_decimal function to convert a Roman numeral to its decimal equivalent and a custom_sort function that separates the name and Roman numeral, converting the latter to decimal for sorting.
See text below
Given a list of strings comprised of a name and a Roman numeral, sort the list first by name, then by the decimal value of the Roman numeral. In Roman numerals, a value is not repeated more than three times. At that point, a smaller value precedes a larger value to indicate subtraction. For example, the letter I represents the number 1, and V represents 5. Reason through the formation of 1 to 10 below and see how it is applied in the following lines.
I, II, III, IV, V, VI, VII, VIII, IX, and X represent 1 through 10.
XX, XXX, XL, and L are 20, 30, 40, and 50.
For any other two-digit number < 50, concatenate the Roman numeral(s) that represent its multiples of ten with the Roman numeral(s) for its values < 10. For example, 43 is 40 + 3 = XL + III = XLIII.
Example