Probability of a randomly chosen car need to be repaired
=
0.81576
Step-by-step explanation:
In one year period
Probability of a randomly chosen car to be repaired once
=
20
%
=
20
100
=
0.2
Probability of a randomly chosen car not to be repaired once
=
1
−
0.2
=
0.8
Probability of a randomly chosen car to be repaired twice
=
6
%
=
6
100
=
0.06
Probability of a randomly chosen car not to be repaired twice
=
1
−
0.06
=
0.94
Probability of a randomly chosen car to be repaired three or more
=
2
%
=
2
100
=
0.02
Probability of a randomly chosen car not to be repaired three or more
=
1
−
0.02
=
0.98
Probability of a randomly chosen car not to be repaired
=
0.2
×
0.94
×
0.98
=
0.18424
Probability of a randomly chosen car need to be repaired = 1 - Probability of a randomly chosen car not to be repaired
=
1
−
0.18424
=
0.81576