Question

Two ladybugs are riding on a turntable as it rotates at 15 rpm as shown in figure 1. What is the period of the turntable

Answer 1

The period of the turntable can be calculated using the formula T = 1/f, where T is the period and f is the frequency. The turntable rotates at 15 rpm, which can be converted to a frequency of 0.25 Hz. Therefore, the period of the turntable is 4 seconds.

Step-by-step explanation:

The period of the turntable can be calculated using the formula T = 1/f, where T is the period and f is the frequency. The question states that the turntable rotates at 15 rpm, which stands for revolutions per minute. To convert this to the frequency in hertz (Hz), we divide the rpm by 60 (since there are 60 seconds in a minute). Therefore, the frequency is 15/60 = 0.25 Hz. Substitute this value into the formula to find the period: T = 1/0.25 = 4 seconds.

Answer 2

The period of the turntable is 4 seconds per revolution.

How did we get the value?

The period of a rotation or revolution is the time it takes for one complete cycle. In the case of a turntable, the period (T) can be calculated using the formula:

`\[ T = \frac{1}{\text{Rotations per minute (rpm)}} \]`

In this scenario, the turntable is rotating at 15 rpm. To find the period, plug in the value:

`\[ T = \frac{1}{15 \, \text{rpm}} \]`

`\[ T = (1)/(15) \, \text{min/rev} \]`

To convert the period to seconds, we multiply by 60 (the number of seconds in a minute):

`\[ T = (1)/(15) * 60 \, \text{s/rev} \]`

`\[ T = 4 \, \text{s/rev} \]`

So, the period of the turntable is 4 seconds per revolution.