A parallel-plate capacitor has a voltage v = 6. 0 v between its plates. each plate carries a surface charge density σ = 7. 0 nc/m2. what is the separation of the plates?

Question

asked May 28, 2024 223k views

1 Answer

Angel Hadzhiev · Answer 1 · 2024-06-02T11:16:00+0000

The separation of the plates of the parallel-plate capacitor is approximately 1.328 mm.

To find the separation of the plates of a parallel-plate capacitor, we can use the formula:

d = σ / (ε0 * v)

where

d is the separation between the plates

σ is the surface charge density

ε0 is the permittivity of free space

v is the voltage between the plates.

Plugging in the given values:

d = (7.0 * 10-9 C/m2) / (8.85 * 10-12 C2/N*m2 * 6.0 V)

d = 1.328 * 10-3 m

Therefore, the separation of the plates is approximately 1.328 mm.