Question

What's the derivative of
`\tt {a}^(2) + {x}^(2)`
Please help! ​

Answer 1

2x

Explanation:

let,
`\tt f(x) = a^2+x^2`

Differentiating both side with respect to x.

`\tt (d)/(dx)f(x) = (d)/(dx)(a^2+x^2)`

Using sum/difference rule

`\tt (d)/(dx)f(x) = (d)/(dx)(a^2) + (d)/(dx)(x^2)`

Now, using Power rule of derivative :
`\boxed{\tt x^n=nx^((n-1))}` .

`\tt f'(x)=0+2x^(2-1)`

`\tt f'(x}=0+2x`

`\tt f'(x)= 2x`

Therefore, the derivative of
`\tt a^2+x^2` is 2x.

Note: derivative of constant term is 0. here a^2 is constant.