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What's the derivative of
\tt {a}^(2) + {x}^(2)
Please help! ​

User Sirclesam
by
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1 Answer

7 votes

Answer:

2x

Explanation:

let,
\tt f(x) = a^2+x^2

Differentiating both side with respect to x.


\tt (d)/(dx)f(x) = (d)/(dx)(a^2+x^2)

Using sum/difference rule


\tt (d)/(dx)f(x) = (d)/(dx)(a^2) + (d)/(dx)(x^2)

Now, using Power rule of derivative :
\boxed{\tt x^n=nx^((n-1))} .


\tt f'(x)=0+2x^(2-1)


\tt f'(x}=0+2x


\tt f'(x)= 2x

Therefore, the derivative of
\tt a^2+x^2 is 2x.

Note: derivative of constant term is 0. here a^2 is constant.

User Olof Larsson
by
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