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write a public static method named range that will take an int array as it's only argument. this method will return an int value. when called, and passed an array of int values, this method will compute and return the positive difference between the minimum of all the values in the argument array, and the maximum of all the values in the argument array.

User Dvsoukup
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2 Answers

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Certainly! Let's break this task into smaller steps:

1. Define the method signature.

2. Find the minimum and maximum value in the array.

3. Compute the positive difference between maximum and minimum.

4. Return this value.

Now, let's write the method in Java:

```java

public class ArrayUtils {

public static int range(int[] array) {

// Step 2: Find the minimum and maximum value in the array.

// If the array is empty or null, we return 0 as range doesn't make sense in such cases

if (array == null || array.length == 0) {

return 0;

}

int minValue = array[0];

int maxValue = array[0];

// Iterate through the array to find the minimum and maximum values

for (int i = 1; i < array.length; i++) {

if (array[i] < minValue) {

minValue = array[i];

} else if (array[i] > maxValue) {

maxValue = array[i];

}

}

// Step 3: Compute the positive difference

int range = maxValue - minValue;

// Step 4: Return the positive difference

return range;

}

public static void main(String[] args) {

int[] array = {5, 2, 9, 1, 5, 6};

System.out.println("Range: " + ArrayUtils.range(array)); // Output: 8

}

}

```

Now let's explain each part:

1. `public static int range(int[] array)` - This is the method signature. It's `public` so it can be accessed from outside the class. It's `static` meaning you don't need an instance of the class to use this method. It takes an array of integers as its only parameter and returns an integer.

2. Inside the method, first, we check if the input array is `null` or empty. If it is, we return 0, as it doesn't make sense to calculate the range in such cases.

3. We initialize `minValue` and `maxValue` with the first element of the array. Then, we iterate through the array to find the minimum and maximum values.

4. The range is the positive difference between the maximum and minimum values, so we subtract the minimum value from the maximum value (`maxValue - minValue`) and store it in a variable called `range`.

5. Finally, we return the `range`.

6. The `main` method is just a driver to test our range method. It creates an array of integers and prints out the range by calling the `range` method.

This method effectively computes the range of an array by iterating through its elements once, which makes it efficient and its time complexity is O(n), where n is the number of elements in the array.

User Alexey Chernikov
by
8.2k points
4 votes

Here's an example of how you could write the range method in Java:

public static int range(int[] arr) {

int min = arr[0]; // initialize min to the first element of the array

int max = arr[0]; // initialize max to the first element of the array

// loop through the rest of the elements to find the min and max

for (int i = 1; i < arr.length; i++) {

if (arr[i] < min) {

min = arr[i];

}

if (arr[i] > max) {

max = arr[i];

}

}

// compute and return the range

return max - min;

}

This method first initializes the min and max variables to the first element of the array, and then loops through the rest of the elements to find the actual minimum and maximum values. Finally, it computes and returns the positive difference between the maximum and minimum values, which represents the range of the array.

User The Red Fox
by
8.0k points

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