Question

Identify which of the following molecules can exhibit hydrogen bonding as a pure liquid. Check all that apply.

Answer 1

Methanol (CH3OH) and N,N-dimethylamine ((CH3)3N) can exhibit hydrogen bonding as pure liquids.

Step-by-step explanation:

The molecules that can exhibit hydrogen bonding as a pure liquid are CH3OH and (CH3)3N. Methanol (CH3OH) can form hydrogen bonds because it contains both a hydrogen atom attached to oxygen (making it a hydrogen bond donor) and two lone pairs of electrons on oxygen (making it a hydrogen bond acceptor). N,N-dimethylamine ((CH3)3N) can also form hydrogen bonds as it has a nitrogen atom that can act as both a hydrogen bond donor and acceptor.

CH3OH can form hydrogen bonds by acting as either a hydrogen bond donor or a hydrogen bond acceptor. The hydrogen-bonded structure of methanol is as follows:

Answer 2

The molecules that exhibit hydrogen bonding are

• ammonia NH3,
• acetic acid
• CH3CO2H
• H2C20H

What is hydrogen bonding?

A hydrogen atom that is covalently bound to a more electronegative atom and another electronegative atom with a lone pair of electrons exhibit an electrostatic force of attraction known as hydrogen bonding. The acceptor is the hydrogen bond.Hydrogen bonding is not a covalent link to a hydrogen atom; rather, it is a unique kind of dipole-dipole interaction between molecules. It arises from the attraction force between another extremely electronegative atom and a hydrogen atom covalently bound to a very electronegative atom, such as an N, O, or F atom.

Therefore, ammonia (NH3), acetic acid (CH3CO2H), and hydrogen bonding (H2C20H) are the molecules that display hydrogen bonding.

The question is incomplete missing options are ;

N2H4

CF2H2

HCl

CF4

*H3CO2H

*C2H2O4

H2C2OH