Question

Review. A 12.0-kg object hangs in equilibrium from a string with a total length of L=5.00m and a linear mass density of μ = 0.00100kg/m . The string is wrapped around two light, frictionless pulleys that are separated by a distance of d=2.00m (Fig. P18.71a).(a) Determine the tension in the string.

Answer 1

The tension in the string holding a 12.0-kg object in equilibrium is calculated as the product of the mass and the acceleration due to gravity, resulting in 117.6 N.

Step-by-step explanation:

To determine the tension in the string holding a 12.0 kg object in equilibrium, we use the fact that the tension must balance out the weight of the object. The weight (W) is given by the product of the mass (m) and the acceleration due to gravity (g), which is approximately 9.8 m/s2 on Earth's surface.

The tension (T) in the string can therefore be calculated as:

T = m × g = 12.0kg × 9.8m/s2 = 117.6N

As the object is in equilibrium and not accelerating, the tension throughout the string will be the same, ignoring any potential sag in the string.