Question

What are the values for θ that satisfy the equation sinθ cosθ-cos θ=0 for 0 ≤ θ<2 π?

Answer 1

Answer:
`\theta=0, (\pi)/(2)`

Explanation:

`\sin \theta \cos \theta-\cos \theta=0\\\\\cos \theta(\sin \theta-1)=0\\\\\implies \cos \theta=0, \sin \theta-1=0\\\\\cos \theta=0, \implies \theta=0\\\\\sin \theta-1=0 \implies \sin \theta=1 \implies \theta=(\pi)/(2)\\\\\therefore \theta=0, (\pi)/(2)`