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What values for θ(0 ≤ θ<2 π) satisfy the equation 3sin θ+1=sinθ ?

1 Answer

3 votes

Answer:
\theta=(7\pi)/(6), \frac{11\pi}6}

Explanation:


3\sin \theta+1=\sin \theta\\\\2\sin \theta+1=0\\\\2\sin \theta=-1\\\\\sin \theta=-(1)/(2)\\\\\theta=(7\pi)/(6), \frac{11\pi}6}

User Tarun Khurana
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