Answer:
x=2 and y=3.
Explanation:
We can solve this by multiplying the inverse of the matrix on the left side of the equation with the matrix on the right side of the equation. The inverse of a 2x2 matrix is given by:
[a b]^-1 = 1/(ad-bc) [d -b]
[-c a]
So we can find the inverse of the matrix on the left side of the equation as follows:
[2 3]^-1 = 1/(2*2-3*1) [2 -3] = [-2 3]
[-1 2]
Multiplying this with the matrix on the right side of the equation gives us:
[-2 3] [5] [x]
[-1 2] [4] = [y]
Which can be written as:
-2x + 3y = 5
-x + 2y = 4
We can solve this system of equations using substitution or elimination. Let’s use substitution. From the second equation, we can write:
x = 2y - 4
Substituting this into the first equation gives us:
-2(2y-4) + 3y = 5
-4y + 8 + 3y = 5
-y = -3
y = 3
Substituting this value of y into either of the equations gives us:
x = 2(3) - 4
x = 2
so
x=2 and y=3.