201k views
2 votes
4t^2-5 find the zeroes of polynomial

User Jingwei
by
8.4k points

1 Answer

7 votes

Answer:

t =
(√(5) )/(2) ,
(-√(5) )/(2)

Explanation:

4
t^(2) - 5 = 0 Add 5 to both sides

4
t^(2) = 5 Divide both sides by 4


t^(2) =
(5)/(4) Take the square root of each side


\sqrt{t^(2) } = ±
\sqrt{(5)/(4) }

t = ±
(√(5) )/(2)

User Manish Balodia
by
8.2k points

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