Question

How many grams of 100 °C water would boil away if 9.20 kJ of energy were added to it?

Heat of Fusion of Water: 2260. J/g

Answer 1

Step-by-step explanation:

The water is at the boiling point.....

you are given kJ and J/g and want to find 'g'

kJ * 1000 = J

9200 J / (2260 J/g) = 4.07 g