Answer:
F
Explanation:
In Quadrant II, the sine of an angle is positive, but the cosine of an angle is negative. Given that sin θ = 3/5 and θ is in Quadrant II, we can use the Pythagorean identity to find the cosine of θ.
Using the Pythagorean identity:
sin² θ + cos² θ = 1
Substituting the given value:
(3/5)² + cos² θ = 1
9/25 + cos² θ = 1
cos² θ = 1 - 9/25
cos² θ = 16/25
cos θ = ±√(16/25)
Since we're in Quadrant II where the cosine is negative, we take the negative square root:
cos θ = -√(16/25)
cos θ = -4/5
Therefore, the value of cos θ when sin θ = 3/5 and θ is in Quadrant II is F. -4/5.