Question

(a) When a battery is connected to the plates of a 3.00-μF capacitor, it stores a charge of 27.0μC . What is the voltage of the battery?

Answer 1

9.00 volts.

Step-by-step explanation:

V = Q / C

Given:

Charge (Q) = 27.0 μC

Capacitance (C) = 3.00 μF

Plugging in the values into the equation:

V = 27.0 μC / 3.00 μF

V = 9.00 volts