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Using the cosine rule figure out angle θ to the nearest degree

Using the cosine rule figure out angle θ to the nearest degree-example-1
User Rothens
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6 votes

Answer:

θ = 36°

Explanation:

The Law of Cosines has three equations:

a^2 = b^2 + c^2 - 2bc * cos (A)

b^2 = a^2 + c^2 - 2ac * cos (B)

c^2 = a^2 + b^2 - 2ab * cos (C)

Let's call the 15 mm side c, the 23 mm side a and the 12 mm side b, and angle θ angle C . Thus, we can use the third equation and plug in 15 for c, 23 for a, and 12 for b to find the measure of angle C (i.e., the measure of θ to the nearest degree):

Step 1: Plug in 15, 23, and 12 and simplify:

c^2 = a^2 + b^2 - 2ab * cos (C)

15^2 = 23^2 + 12^2 -2(23)(12) * cos (C)

225 = 529 + 144 - 552 * cos (C)

225 = 673 - 552 * cos (C)

Step 2: Subtract 673 from both sides:

(225 = 673 - 552 * cos (C)) - 673

-448 = -552 * cos (C)

Step 3: Divide both sides by -552:

(-448 = -552 * cos (C)) / -552

-448/-552 = cos (C)

56/69 = cos (θ)

Step 4: Use inverse cosine to find C and round to the nearest degree (i.e., the nearest whole number):

cos^-1 (56/69) = C

35.74801694 = C

36 = C

36 = θ

Thus, angle θ is about 36°.

User Mrk
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