67.8k views
1 vote
Which equation represents the line that is perpendicular to y = 2/5x + 1 and passes through (-10,20)?

A. y = -5/2x - 5

B. y = -5/2x + 40

C. y = 2/5x - 18

D. y = 2/5x + 24

1 Answer

7 votes

Answer:

A. y = -5/2x - 5

Explanation:

To find the equation of the line that is perpendicular to y = (2/5)x + 1, we need to determine the negative reciprocal of the slope of the given line.

The given line has a slope of 2/5. The negative reciprocal of 2/5 is -5/2.

Now, we can use the point-slope form of a linear equation to find the equation of the line that passes through the point (-10, 20) with a slope of -5/2:

y - y1 = m(x - x1)

where (x1, y1) is the given point and m is the slope.

Plugging in the values, we get:

y - 20 = (-5/2)(x - (-10))

y - 20 = (-5/2)(x + 10)

y - 20 = (-5/2)x - 25

y = (-5/2)x - 5

Therefore, the equation that represents the line perpendicular to y = (2/5)x + 1 and passes through (-10, 20) is:

A. y = -5/2x - 5

User Kampta
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories