Answer:
A. y = -5/2x - 5
Explanation:
To find the equation of the line that is perpendicular to y = (2/5)x + 1, we need to determine the negative reciprocal of the slope of the given line.
The given line has a slope of 2/5. The negative reciprocal of 2/5 is -5/2.
Now, we can use the point-slope form of a linear equation to find the equation of the line that passes through the point (-10, 20) with a slope of -5/2:
y - y1 = m(x - x1)
where (x1, y1) is the given point and m is the slope.
Plugging in the values, we get:
y - 20 = (-5/2)(x - (-10))
y - 20 = (-5/2)(x + 10)
y - 20 = (-5/2)x - 25
y = (-5/2)x - 5
Therefore, the equation that represents the line perpendicular to y = (2/5)x + 1 and passes through (-10, 20) is:
A. y = -5/2x - 5