Question

What is the equation of the line that has a slope of 3 and goes through the point (-3,-5)? O A. y = 3x +4 O B. y = 3x - 14 O c. y = 3x - 4 O D. y = 3x + 12

Answer 1

The equation is:

y = 3x + 4

Work/explanation:

First, we will write the equation in point slope:

`\Large\pmb{y-y_1=m(x-x_1)}`

where m = slope;

(x₁, y₁) is a point on the line

Plug in the data:

`\large\begin{gathered}\sf{y-(-5)=3(x-(-3)}\\\sf{y+5=3(x+3)}\\\sf{y+5=3x+9}\\\sf{y=3x+9-5}\\\sf{y=3x+4}\end{gathered}`

Hence, the equation is y = 3x + 4.

Answer 2

A

Explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

given slope m = 3 , then

y = 3x + c ← is the partial equation

to find c substitute (- 3, - 5 ) into the partial equation

- 5 = 3(- 3) + c = - 9 + c ( add 9 to both sides )

4 = c

y = 3x + 4 ← equation of line