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ages of th (c) Five years ago a father's age was 4 times his son's age. Now, the sum of their ages is 45 years. Find their present ages.​

User Davy
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Answer:

Explanation:

Let's assume the father's current age is F, and the son's current age is S.

Five years ago a father's age was 4 times his son's age.

This statement implies that five years ago, the father's age was F - 5, and the son's age was S - 5. According to the given information, we can set up the equation:

F - 5 = 4(S - 5)

Now, the sum of their ages is 45 years.

The sum of their ages now is F + S. According to the given information, we can set up the equation:

F + S = 45

Now we have two equations with two unknowns. We can solve them simultaneously to find the values of F and S.

Let's solve the first equation for F:

F - 5 = 4S - 20

F = 4S - 20 + 5

F = 4S - 15

Substitute this value of F in the second equation:

4S - 15 + S = 45

5S - 15 = 45

5S = 45 + 15

5S = 60

S = 60 / 5

S = 12

Now substitute the value of S back into the equation for F:

F = 4S - 15

F = 4(12) - 15

F = 48 - 15

F = 33

Therefore, the father's present age (F) is 33 years, and the son's present age (S) is 12 years.

User Fuentes
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