Answer:
108.17° (nearest hundredth)
Explanation:
In order to find the direction the person is swimming, we must find the direction of the resultant vector of the two vectors representing 6.4 m/s north and 2.1 m/s west, measured counterclockwise from the positive x-axis.
Since the two vectors form a right angle, we can use the tangent trigonometric ratio.

The resultant vector is in quadrant II, since the swimmer is travelling north (positive y-direction) and is being pushed by a current moving west (negative x-direction).
As the direction of a resultant vector is measured in an anticlockwise direction from the positive x-axis (and the resultant vector is in quadrant II), we need to add 90° to the angle found using the tan ratio.
The angle between the y-axis and the resultant vector can be found using tan x = 2.1 / 6.4. Therefore, the expression for the direction of the resultant vector θ is:



Therefore, the direction of the swimmer's resultant vector is approximately 108.17° (measured anticlockwise from the positive x-axis).
This can also be expressed as N 18.17° W.