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Please help!!!! Thank you so much (don’t mind what’s already typed in the answer box, I’m confused with the whole thing)

A polynomial f(x) has the given zeros of 6, -1, and-3
Part A: Using the Factor Theorem, determine the polynomial f(x) in expanded form. Show all necessary calculations (3 points)
Part B: Divide the polynomial f(x) by (x²-x-2) to create a rational function gox) in simplest factored form. Determine gox) and find its stant asymptote (4 points)
Part C: List all locations and types of discontinuities of the function g(x). Be sure to check for all asymptotes and holes. Show all necessary calculations (

Please help!!!! Thank you so much (don’t mind what’s already typed in the answer box-example-1
User Ali Abid
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1 Answer

2 votes

Answer:

Part A:

Using the Factor Theorem, we know that f(x) can be written as:

f(x) = a(x - 6)(x + 1)(x + 3)

where a is a constant that we need to determine.

To find the value of a, we can use one of the given zeros of f(x), for example, x = 6. When x = 6, we know that f(x) = 0, so we can substitute these values into the equation above:

0 = a(6 - 6)(6 + 1)(6 + 3)

Simplifying, we get:

0 = 189a

Therefore, a = 0.

So, the polynomial f(x) is:

f(x) = 0(x - 6)(x + 1)(x + 3)

Simplifying, we get:

f(x) = 0

Part B:

To divide f(x) by (x² - x - 2), we can use long division:

0

___________

x² - x - 2 | 0x³ + 0x² + 0x + 0

- (0x³ - 0x² - 0x)

_______________

0x² + 0x

- (0x² - 0x - 2)

_______________

2x + 2

Therefore, the rational function g(x) in simplest factored form is:

g(x) = (2x + 2)/(x² - x - 2)

To find the vertical asymptotes, we need to find the roots of the denominator:

x² - x - 2 = 0

(x - 2)(x + 1) = 0

Therefore, the vertical asymptotes are x = 2 and x = -1.

To find the horizontal asymptote, we can use the fact that the degree of the numerator is less than the degree of the denominator. Therefore, the horizontal asymptote is y = 0.

Part C:

The function g(x) has two vertical asymptotes at x = 2 and x = -1.

To check for any holes, we can simplify the function by factoring the numerator:

g(x) = 2(x + 1)/(x - 2)(x + 1)

Since we factored the numerator and denominator of g(x), we can see that there is a hole in the graph at x = -1. This is because the factor (x + 1) cancels out in both the numerator and denominator, leaving a hole at that point.

To find the x-intercepts, we need to solve for when the numerator is equal to zero:

2x + 2 = 0

x = -1

Therefore, the x-intercept is (-1, 0).

To find the y-intercept, we can substitute x = 0 into the equation for g(x):

g(0) = 2(0 + 1)/(0 - 2)(0 + 1)

g(0) = -1

Therefore, the y-intercept is (0, -1).

To sketch the graph of g(x), we can use the information we have gathered so far. The graph has two vertical asymptotes at x = 2 and x = -1, a hole at x = -1, an x-intercept at (-1, 0), and a y-intercept at (0, -1). The horizontal asymptote is y = 0.

We can also use the factored form of g(x) to determine the end behavior of the graph. As x approaches positive or negative infinity, the function approaches zero. Therefore, the graph approaches the x-axis on either side of the vertical asymptotes.

Putting all of this information together, we can sketch the graph of g(x) as follows:

[insert graph of g(x) here]

User Renganathan M G
by
7.9k points

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