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If the sum of the zeroes of the polynomial 5x2-px+7 is 9, the find the value of 'p'.​

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I got you Gilbert.

The sum of the zeroes of a quadratic equation in the form of ax^2 + bx + c is given by -b/a. In this case, the sum of the zeroes of the polynomial 5x^2 - px + 7 is 9. Therefore, we can write the equation as:

-b/a = 9

where b = -p and a = 5. Substituting these values, we get:

-(-p)/5 = 9

Simplifying this equation, we get:

p/5 = 9

Multiplying both sides by 5, we get:

p = 45

Therefore, the value of 'p' is 45.
User Bartolome
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