Answer:
The reaction you are referring to is:
Mg + 2AgNO3 → Mg(NO3)2 + 2Ag
0.960 moles of silver will be produced
Step-by-step explanation:
The balanced equation shows that 1 mole of Mg reacts with 2 moles of AgNO3 to produce 2 moles of Ag.
If we start with 0.480 moles of Mg, then we will produce 0.480 * 2 / 1 = 0.960 moles of Ag.
Here is the calculation:
Number of moles of Ag produced = (Number of moles of Mg) * (Moles of Ag produced per mole of Mg)
= 0.480 moles * 2 moles/mole
= 0.960 moles
Therefore, 0.960 moles of silver will be produced if the reaction starts with 0.480 moles of Mg.