Question

Wan has 22 bulbs of the same shape and size in a box. The colors of and amounts of the bulbs are shown below:

6 blue bulbs
9 red bulbs
7 orange bulbs
Without looking in the box, Wan takes out a bulb at random. He then replaces the bulb and takes out another bulb from the box. What is the probability that Wan takes out an orange bulb in both draws? (5 points)

a 7 over 22 multiplied by 7 over 22 equal 49 over 484
b 7 over 22 multiplied by 6 over 21 equal 42 over 462
c 7 over 22 plus 6 over 21 equal 279 over 462
d 7 over 22 plus 7 over 22 equal 308 over 484

Answer 1

484

Explanation:

Answer 2

The probability of taking out an orange bulb on the first draw is 7/22. Since Wan replaces the bulb before the second draw, the probability of taking out an orange bulb on the second draw is also 7/22.

Therefore, the probability of taking out an orange bulb in both draws is:

(7/22) * (7/22) = 49/484

Therefore, the answer is (a) 7 over 22 multiplied by 7 over 22 equal 49 over 484.