Answer:
5 m/s
Step-by-step explanation:
We are given that 9000 kg of water flows through the pipe in 1 minute. Mass flow rate = mass/time
So, mass flow rate = 9000 kg / 1 minute = 150 kg/s
We know the cross sectional area of the pipe is 0.3 m2. From continuity equation, mass flow rate = density * area * velocity
So, 150 = 1000 * 0.3 * v (Density of water is approximately 1000 kg/m3)
Solving for v (velocity):
v = 150/(1000*0.3) = 5 m/s
Therefore, the speed of water in the pipe is 5 m/s.