Question

Help me do this plis

Answer 1

We Know ::

• Sum of all the interior angles of a parallelogram is 360°

So,,

`\begin{gathered} \; :\dashrightarrow \: \tt{(3x - 32)^(\circ) + x^(\circ) + (3x - 32)^(\circ) + x^(\circ) = 360^(\circ)} \\ \\ \end{gathered}`

`\begin{gathered} \; :\dashrightarrow \: \tt{3x - 32 + x + 3x - 32 + x = 360} \\ \\ \end{gathered}`

`\begin{gathered} \; :\dashrightarrow \: \tt{3x + x + 3x + x - 32 - 32 = 360} \\ \\ \end{gathered}`

`\begin{gathered} \; :\dashrightarrow \: \tt{8x - 64 = 360} \\ \\ \end{gathered}`

`\begin{gathered} \; :\dashrightarrow \: \tt{8x = 360 + 64} \\ \\ \end{gathered}`

`\begin{gathered} \; :\dashrightarrow \: \tt{8x = 424} \\ \\ \end{gathered}`

`\begin{gathered} \; :\dashrightarrow \: \tt{x = \frac{\cancel{424}}{\cancel{ \: 8}}} \\ \\ \end{gathered}`

`\begin{gathered} \; :\dashrightarrow \underline{\boxed{\tt{x = 53^(\circ)}}} \: \pmb{\bigstar} \\ \\ \end{gathered}`

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Substituting ( x ) ::

`\begin{gathered} \; \diamond \: \tt{(3x - 32)^(\circ) = (3 * 53 - 32)^(\circ)} \\ \\ \end{gathered}`

`\begin{gathered} \; \diamond \: \tt{(3x - 32)^(\circ) = (159 - 32)^(\circ)} \\ \\ \end{gathered}`

`\begin{gathered} \; :\dashrightarrow \underline{\boxed{\tt{(3x - 32)^(\circ) = 127^(\circ)}}} \: \pmb{\bigstar} \\ \\ \end{gathered}`

`\begin{gathered}{\underline{\pmb{\rule{170pt}{10pt}}}} \end{gathered}`