The chemical reaction for the reaction of strontium hydroxide with hydrobromic acid is:
Sr(OH)2 + 2 HCl --> SrCl2 + 2 H2O
To find the moles of water produced when 5.50 moles of strontium hydroxide are consumed, we need to apply the law of conservation of mass. The mass of water produced is equal to the mass of strontium hydroxide consumed. Since strontium hydroxide has a molar mass of 142 g/mol and water has a molar mass of 18 g/mol, 1 mol of strontium hydroxide can produce 9 mol of water. Therefore, 5.50 moles of strontium hydroxide can produce 49.5 mol of water.
Similarly, 7.50 moles of water can be produced by reacting 18 moles of hydrobromic acid with strontium hydroxide. Hydrobromic acid has a molar mass of 79.9 g/mol, so 18 moles of hydrobromic acid would have a mass of 79.9 * 18 = 1435.2 g.
To find the moles of strontium bromide produced when 10.8 g of strontium hydroxide is used, we need to apply the law of conservation of mass again. The mass of the strontium bromide produced is equal to the mass of strontium hydroxide consumed. Since strontium bromide has a molar mass of 410 g/mol and strontium hydroxide has a molar mass of 142 g/mol, 1 mol of strontium bromide can consume 3.23 moles of strontium hydroxide. Therefore, 10.8 g of strontium hydroxide can produce 10.8 / 3.23 = 3.34 moles of strontium bromide.
Finally, to find the mass of water produced when 13.3 g of hydrobromic acid is consumed, we need to apply the law of conservation of mass yet again. The mass of the water produced is equal to the mass of hydrobromic acid consumed. Since hydrobromic acid has a molar mass of 79.9 g/mol, 13.3 g of hydrobromic acid would produce 13.3 / 79.9 = 0.166 moles of water.