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A soil contains 2000 mg N/ kg of soil in organic forms. The rate of mineralization is 3% per year. A) How many mg of N/ kg of soil is mineralized every year? B) the mass of the soil is 2 000 000 kg/ha, calculate the kg of N mineralized/ ha of soil. Show your work.

User Guzmonne
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1 Answer

6 votes

Answer:

a) how many mg of n/ kg of soil is mineralized every year? Nitrogen mineralized every year = 60 mg N/kg of soil

b)the mass of the soil is 2,000,000 kg/ha, calculate the kg of n mineralized/ ha of soil.

120 kg/ha of nitrogen is mineralized every year.

Step-by-step explanation:

To calculate the amount of nitrogen mineralized every year, we can use the formula:

Nitrogen mineralized every year = Nitrogen in organic forms x Mineralization rate

From the problem statement, we know that the soil contains 2000 mg N/kg of soil in organic forms and the rate of mineralization is 3% per year.

Substituting these values into the formula above, we get:

Nitrogen mineralized every year = 2000 mg N/kg of soil x 3%

Nitrogen mineralized every year = 60 mg N/kg of soil

To calculate the kg of N mineralized/ha of soil, we can use the formula:

kg of N mineralized/ha of soil = (Nitrogen mineralized every year x Mass of soil)/1000

From the problem statement, we know that the mass of the soil is 2 000 000 kg/ha.

Substituting these values into the formula above, we get:

kg of N mineralized/ha of soil = (60 mg N/kg of soil x 2 000 000 kg/ha)/1000

kg of N mineralized/ha of soil = 120 kg/ha

Therefore, 120 kg/ha of nitrogen is mineralized every year.

User Brandt
by
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